Hello,
I am doing precipitation of 5 g of BaCl
2ยท2H
2O, 5 g of CaCO
3 and 3,7 g of K
2SO
4 in 100 ml of H
2O in laboratory next week and I just need confirmation that I assume correct reactions.
CaCO
3 isn't soluble at all, so firstly happens BaCl
2+K
2SO
4 BaSO4
+2KCl.
CaCO
3 and BaSO
4 is then vacuum filtrated and KCl solution is left for crystalization.
Then I put 100 ml of dilluted HCl in the beaker with filter cake, so this happens,
CaCO
3+2HCl
H
2CO
3(boiling)
+CaCl
2, so another filter cake from vacuum filtration will consist of BaSO
4.
Now I put solution with CaCl
2 together with 5,5 g solution of Na
2CO
3 in 40 ml of water together, so what happens is
CaCl
2+Na
2CO
3 CaCO
3 +2NaCl.
Calcium carbonate is then vacuum filtrated.
Is it how it works, or am I missing something crucial?
Thanks for help.