Hi guys! I need help with a certain question:
Compound X
pKa = 9.45
Solubility = 61.7 mg/L
MW = 259.34
Calculate solubility at pH 4.2 in mg/L
I got some wierd answer with like 10 million so i dont think im correct
Assuming Basic due to pKa:
pH = pKa + Log(s0/s-s0)
4.2 = 9.45 + Log(61.7/s-61.7)
-5.25 = Log(61.7/s-61.7)
10^-5.25 = 61.7/s-61.7
(61.7 รท 10^-5.25) + 61.7 = s
s = 10972045.66 mg/L (2d.p.)