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How to derive ΔG∘=−RTlnKeq from ΔG∘= ΔH∘-T ΔS∘?

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AussieKenDoll:
How to derive ΔG∘=−RTlnKeq from ΔG∘= ΔH∘-T ΔS∘?

AussieKenDoll:
How to derive ΔG∘=−RTlnKeq from basic thermodynamic principles?

Borek:
I have merged your threads as they are very similar.

You have to show your attempts at answering the question before receiving help, this is a forum policy.

Have you tried to google?

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