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Topic: Verification: Avg. Oxidation Number Question  (Read 3480 times)

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Offline Atome

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Verification: Avg. Oxidation Number Question
« on: August 13, 2008, 10:26:29 AM »
Hello everyone,

For the following practice problem, I arrived at the same answer as the one in my textbook. However, I am studying for AP Chemistry by myself and since the textbook does not explain the answer, could someone please verify my solution?

Thank you.

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1. The compound Fe3O4 contains both Fe2+ and Fe3+ ions. What is the average oxidation number of iron in this oxide?

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Since oxygen's oxidation state is -2, the "equation" representing oxidation states would be:

Oxidation State of Fe3 + (-2 x 4) = 0

Therefore:

Oxidation State of Fe3 = 8

Oxidation State of Fe  = 8/3

= Avg. Oxidation State because the ionic charge is irrelevant.


Offline Yggdrasil

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Re: Verification: Avg. Oxidation Number Question
« Reply #1 on: August 13, 2008, 11:08:03 AM »
Your answer looks correct.  Now for fun, can you figure out how many iron (III) and iron (II) ions are in Fe3O4?

Offline Atome

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Re: Verification: Avg. Oxidation Number Question
« Reply #2 on: September 07, 2008, 09:02:22 AM »
Thanks for your response, yggdrasil. I missed your question.

Would there be three ferrous and ferric ions in Fe3O4?


Offline Borek

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Re: Verification: Avg. Oxidation Number Question
« Reply #3 on: September 07, 2008, 09:45:37 AM »
Fe3O4 can be treated as mixed oxide Fe2O3.FeO.
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