Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: alexanda on October 29, 2015, 11:34:34 PM
-
i was taught that the electron configuration of copper is [Ar] 4s1 3d10 and only unpaired electron in 3d can be used for bonding,so my question is, why there is cu2+ with [Ar] 3d9 , a paired electron is used for bonding?
iron(lll) ion is another example that i can't understand with [Ar] 3d5, again, why a paired electron can still be used for bonding
hope any one can reply me asap .Thanks a lot:D
-
Copper can also be [Ar] 4s2 3d9 And then the 2 s- Electrons do the bonding. The electron configuration [Ar] 4s1 3d10 is valid for the element itself, and this is more stable. This phenomena you can find at several transition elements. Like chromium, iron, palladium and others.
-
so do you mean that most of the Cu exist in [Ar] 4s1 3d10 ,but small amount of them exist in [Ar] 4s2 3d9 which the 2 electrons within the 4s subshell can be used for bonding?
-
It can convert to it. [Ar] 4s1 3d10 is one element to early in the row. In order [Ar] 4s2 3d9 would be first. At zinc the shell is full with [Ar] 4s2 3d10.