Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: Mal1ce on September 12, 2010, 12:12:28 AM
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The Problem:
The solubility-product constant for K2PdCl6 is 6.0 x 10-6 (K2PdCl6 <--> 2K+ + PdCl2-6). What is the K+ concentration of a solution prepared by mixing 50.0 mL of 0.400 M KCl with 50 mL of 0.100 M PdCl2-6.
The first thing I did was find the new concentrations of K+ and PdCl2-6, [K+] = 0.2 M and [PdCl2-6] = 0.05 M. Here is where I am stuck. I am assuming that these new concentrations are the initial concentrations and I need to find the equilibrium concentration of K+. How do I use these initial concentration and the solubility-product constant to find the concentration of K+? Do I need to use the ICE box to solve this problem? If anyone could walk me through on how to solve this problem it would be greatly appreciated. Thanks in advance.
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Limiting reagent.
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I don't understand how this is a limiting reagent problem.
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Are they mixed in stoichiometric amounts?