Hallo, nice to meet you. I'm new to this forum.
Hey everyone, can someone give me the half equations for this reaction
6H2S + 2HNO3 -> 6S + 2NO + 4H20
can we write, that :
LSH : 6H
2S+2HN
(+5)O
3-->12H
++6S
-2+2H
++2NO
3-->14H
++6S
-2+2N
(+2)O-6e
-+4O
-2->4H
2O+2NO+6S
-2+(6H
+-6e
-)
->4H
2O+2NO+6S+6(H
++e
-)
->6S+2NO+4H
2O+(3H
2) X ?
but maybe it could be written (to be experimentally checked), that 1electron, or negative charge, would become 1 anti-proton : 1e
-->1
p-, which would annihilate the H+ ion :
->4H
2O+2NO+6S+6(H
++
p-) (lack of mass balancing, or energy : - E=6(m
p-m
e)c
2) ?
->6S+2NO+4H
2O (-E, and hence an endothermic reaction) ?
cya.
PS.: could this be used to build a "chemical temperature regulator" ? (It were welcomed by such a hot summer)