Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: diah on October 17, 2013, 03:52:44 PM
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If you're given a reaction, such as;
2O(g)-->O2(g) with delta H=-249 kJ/mol OR
C(graphite)+2H2(g)-->CH4(g) with delta H=-75 kJ/mol
then how do you calculate the heat of combustion of methane into gaseous H2O?
I found the enthalpies of H2O(g) which is -241.8 kJ/mol and CH4 is -74.9 kJ/mol, do you use the equation of delta H=(sum of products)-(sum of reactants) or something else?
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Always start with a balanced chemical reaction equation. Which in your case would be.... what do you think?
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Would you add in O2 and CH4 on the reactant side and then H2O(g) on the product side?
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You're missing something. And also, you need to balance the equation.
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I got 4O(g)+CH4(g)-->2H2O(g)+CO2(g)
What is missing?
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You must be careful. Methane doesn't react with "O(g)".