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Topic: What is the molarity of an acetic acid solution prepared by diluting 200.0 ml of  (Read 6445 times)

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Offline tkelley

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What is the molarity of an acetic acid solution prepared by diluting 200.0 ml of
« on: April 25, 2006, 09:12:56 AM »
Sorry about this but having problems with this type of problem... 

What is the molarity of an acetic acid solution prepared by diluting 200.0 ml of .500M HC2H3O2  to a tolal of 1.00L 

I just need help with the general set up if possible.   
thanks tom
« Last Edit: April 25, 2006, 01:52:03 PM by Mitch »
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Offline Albert

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Re: One more question...
« Reply #1 on: April 25, 2006, 09:17:07 AM »
Multiplying a volume by a molar concentration (M) you'll get the moles of that substance.

Then, moles/volume = concentration.
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Offline Borek

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Re: One more question...
« Reply #2 on: April 25, 2006, 10:45:42 AM »
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Offline tennis freak

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Re: What is the molarity of an acetic acid solution prepared by diluting 200.0 ml of
« Reply #3 on: May 17, 2006, 06:31:24 PM »
my suggestion would be the equation mv=mv where the initial molarity times the initial volume equals the final molarity times the final volume.  just solve for m by dividing the original mv by the second v and you have your answer.
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Offline syko sykes

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Re: What is the molarity of an acetic acid solution prepared by diluting 200.0 ml of
« Reply #4 on: May 17, 2006, 08:58:53 PM »
Quote from: tennis freak on May 17, 2006, 06:31:24 PM
my suggestion would be the equation mv=mv where the initial molarity times the initial volume equals the final molarity times the final volume.  just solve for m by dividing the original mv by the second v and you have your answer.
and don't forget conversions, i.e. .2L not 200mL

should end up with .1M for answer
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Offline tennis freak

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Re: What is the molarity of an acetic acid solution prepared by diluting 200.0 ml of
« Reply #5 on: May 17, 2006, 09:55:53 PM »
Quote from: syko sykes on May 17, 2006, 08:58:53 PM
Quote from: tennis freak on May 17, 2006, 06:31:24 PM
my suggestion would be the equation mv=mv where the initial molarity times the initial volume equals the final molarity times the final volume.  just solve for m by dividing the original mv by the second v and you have your answer.
and don't forget conversions, i.e. .2L not 200mL

should end up with .1M for answer

right nice catch dude ;D
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