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Specialty Chemistry Forums => Biochemistry and Chemical Biology Forum => Topic started by: fredodgers on September 20, 2014, 02:24:04 PM

Title: Titration of lysine
Post by: fredodgers on September 20, 2014, 02:24:04 PM

Hello,

I am stuck on a question concerning the titration of lysine.  The question is the following: If the titration of lysine is done by adding OH- to a solution that has 2 moles of lysine, how many moles of NaOH would have to be added to get to 2.5 equivalent?

The answer is 5 moles, but I do not see how to get there.  Wouldn't two moles of lysine have 6 equivalents in total?  How would you go about using that information to get to the answer?

I thank in advance for the help

Title: Re: Titration of lysine
Post by: Babcock_Hall on September 20, 2014, 04:28:02 PM

Would it be possible to provide the exact wording of the question?

Title: Re: Titration of lysine
Post by: Irlanur on September 21, 2014, 08:57:54 AM

2*2.5=5