What happens, at molecular level, while evaporating an aqueous solution of a base, B if ammonia is present in the same solution? (pka of conjugated BH+ is say about 10)
So in the solution there is: BH+, OH-, NH4+
What is supposed to be left after the evaporation is a free base B, correct?
Why not a hydroxide BH+OH-(s) or something like this? Or can [BH+OH-] be an intermediate - the last species just before last water is expelled.
(As evaporation goes on most of NH3 is liberated from the solution and pH is dropping. To neutral ??
If it's indeed neutral the base is already protonated, BH+. So we should have BH+ and OH- instead of just B in H2O.)
Comment welcome