Because of the octest rule?

Guess: The only factors at play here are the nuclear charge which without slater's rules we only use a Z_eff estimate play a constant rate increasing effect going across the column left to right.

If the atomic radius isn't dropping as heavily as atomic number increases across a period, the only possibility is the shielding is increasing across the period. But that's a contradiction because you inner shell isn't changing across the same period.

 Why is the slope in order of smallest to 1. largest main group (1-2), 2. transition metals, 3. main groups 13-18?

gp1/2 ionic radius sharper drop


With the exception of phosphide, the difference in ionic radius between successive anion forming non-metals is smaller than that between group I and group II's cations

What explains this slope ( atomic radius to atomic number) besides the Bohr radius trend for isoelectronic to hydrogen elements is applicable to just about all atoms in the main group?

Why is the Bohr radius (slope versus atomic number) trend in the figure below consistent for atoms non-isoelectronic to Hydrogen?


Why is the following true besides it is consistent with Slater's rules? "Lithium has but 3 protons in its nucleus. Adding a fourth, to make it beryllium, increases the nuclear charge by 33%. But if you add yet another proton, to make it boron, you are increasing the nuclear charge by 25%. And so on, down to the change from oxygen to fluorine, an increase in the nuclear charge (really, the proton count) of only 12.5%. This accounts for the decline in rate of change that you observ

It should be the cis - 4-bromo-2R,3R epoxy- butan-1-ol.

Hello!
I'm watching an ACS Ochem 2 Exam Review: https://www.youtube.com/watch?v=OQctLH-psYc&list=PL3A1cf8LCsnlSRO3HEygntDa4cd9tQh2U&index=1

At timestamp 4:30, we are assigning R and S configuration for the epoxide's carbon #3. We are comparing the carbon with O, C, H, and the carbon connected to Br, H, H. The carbon connected to OCH is given 2nd priority, and the carbon with BHH is given 3rd priority. Why is that? I thought since Br has the higher mass, it would have 2nd priority?

I also found a similar question on R/MCAT: https://www.reddit.com/r/Mcat/comments/91mzf1/br_or_oh_higher_priority/

I would appreciate the clarification. Thank you for your time and patience!