Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: kal215 on March 15, 2015, 11:23:50 PM
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hello,
I don't understand the purpose of Iodine in a grignard reaction with bromobenzene, and magnesium in diethyl ether!
I think I read somewhere that the iodine improves the reactivity of this reaction? :/
I am not sure how this reaction mechanism would look like..
If anyone has feedback, that would be great.
have a good day!
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The Iodine activates the magnesium to form the Grignard by building of Mg2+. One drop of bromine will also do, but iodine easier to handle.
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Hey, thank you for the response.
Interesting.
Hm, I wonder what does the iodine do to activate the Mg?
Ive read also that Iodine is used to indicate if the Grignard reaction has begun. That a iodine crystal dissolved into a bromobenzene solution with magnesium turnings would be a reddish brown, and once the grignard reaction begins the solution will turn clear...
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It the same thing. Mg + I2 => Mg2+ + 2 I- Left side brown, right side colorless.
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I've never quite understood what the iodine does... How does formation of a small amount of Mg(II) facilitate the oxidative addition of more Mg(0) into the C-X bond? Lewis acid activation of C-X maybe? Or does it just break up the surface of the Mg to give a greater surface area? I've also used 1,2-dibromoethane (which presumably forms ethylene) and mechanical activation of the magnesium itself, both of which work very well.