Chemical Forums
Specialty Chemistry Forums => Chemical Engineering Forum => Topic started by: gumusonur on December 03, 2020, 05:22:33 AM
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hi everyone,
you know Adblue?
they says Adblue include 32,5 urea in deinozed water. but ı cant believe. in this case, the price they sell is not appropriate.
ı tried. ı have a %46 urea (Solid). how can ı do %32.5 urea solution from this product? i cant solve.
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Did you know that Adblue contains urea of the highest purity?
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you can see following link.
https://www.total.co.uk/adblue-what-made-how-work#:~:text=AdBlue%C2%AE%20is%20made%20of,before%20it%20enters%20the%20atmosphere.
ı dont know. do you believe this product include %32,5 urea?
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46% (nitrogen content) of urea contains about 98.5% of urea and almost 1.5% of impurities, mainly anti-caking additives.
Saving can be expensive.
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so, i have %98,5 Urea and this urea include %46 N?
I am sending it in the attachment. sorry for not clear.
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You urea contains a guaranteed content of 46.33% N which corresponds to the purity of urea 99.3%
https://primerdigital.com/tools/UniDilution.html
On your own responsibility!
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thanks for reply.
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This may not be relevant, but if you need the urea to be free of ammonium cyanate (which is in equilibrium with urea), you can use a mixed-bed ion-exchange resin to remove the ions. The solution can be checked by conductivity.
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thanks Babcock_Hall.
on the other hand, what should be the conductivity of the urea solution? Is conductivity important to prevent collapse?
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http://www.bio-rad.com/webroot/web/pdf/psd/literature/LIT205.pdf
With respect to your first question, 6 M urea can be reduced from 70 µmho/cm to 0.2 µmho using the column method (see Table 3 in the link). The batch method does not look as effective. I don't know the answer to your second question. Biochemists like to remove cyanate from urea because it reacts with lysine side chains in proteins; in other words, conductivity is not the issue itself, only a measurement tool. I hope that some of this is useful information to you, but I am concerned that I might be going off on a tangent.
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thanks : )