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Topic: Ka at 25% equivalence  (Read 3297 times)

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Sheryl Mackie

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Ka at 25% equivalence
« on: March 14, 2006, 08:08:25 PM »
I need to find the Ka of acetic acid at 25% of equivalence. The initial solution is 5 mL of .600M acetic acid mixed into 100 mL distilled water. This is titrated with 4 mL of .186M NaOH at 25% equivalence.

How do I find Ka at 25% equivalence?

Thank you,

Sheryl
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Offline AWK

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Re:Ka at 25% equivalence
« Reply #1 on: March 15, 2006, 02:51:58 AM »
Ka you can find in tables. You probably should calculate pH at this point!?
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Offline Borek

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Re:Ka at 25% equivalence
« Reply #2 on: March 15, 2006, 03:46:56 AM »
Sheryl: Ka is only temperature dependent, concentration or titration percent do not change Ka value.
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