Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Organic Chemistry Forum for Graduate Students and Professionals => Topic started by: Dan on August 01, 2012, 08:11:52 PM
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Rationalise the following transformation:
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No takers?
Hint: Amadori
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Hint: Carbanionic migration
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Hi,
with your hints (and a few beers), I put together a suggestion towards the solution.
Best
edit: resize of png
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Yes, well done!
The benzilic acid rearrangement proceeds with very high diastereoselectivity. Can you rationalise the stereochemistry?
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Long time no see Dan. How are you doing? :)
My explanation for the diastereoselectivity is that the methyl group migration of C to give D is stereoelectronically forbidden, for a carbonyl group that bears highly distorted bond angles would be formed. So rearragement of A to B is favored.
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Hi Rory, I'm fine thanks.
I am not convinced by your distorted bond argument. As drawn, both of those migration products have distorted sp2 bond angles - this is just an artistic issue, not a real life problem. It is more accurate to draw the carbonyl in a position inbetween the axial and equatorial positions.
I think it is more helpful to consider a 5-membered calcium chelate. Hint: What models are commonly used to rationalise and predict the diastereoselectivity of addition to α-stereogenic aldehydes/ketones?
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I'm sorry for the inconvincable argument. Does Cram rule account for the stereoselectivity?
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Yes - the stereoselectivity of the benzilic acid rearrangement can be rationalised by the chelated Felkin-Ahn model. Well done.