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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Maciejczyk on February 18, 2013, 04:49:28 PM

Title: Molarity task
Post by: Maciejczyk on February 18, 2013, 04:49:28 PM
Hello,

Please can someone explain this task extacly to me?

I would be grateful.

What mass of NaOH (Mr = 40) is required to make 0.5L of a 0.2M solution?
Title: Re: Molarity task
Post by: sjb on February 18, 2013, 05:14:54 PM
Hello,

Please can someone explain this task exactly to me?

I would be grateful.

What mass of NaOH (Mr = 40) is required to make 0.5L of a 0.2M solution?

What are your thoughts? What, for instance does Mr=40 mean, or 0.5L, 0.2M? Please check the forum rules.
Title: Re: Molarity task
Post by: Borek on February 18, 2013, 05:40:31 PM
Please read forum rules (http://www.chemicalforums.com/index.php?topic=65859.0).

You have to show your attempts at solving the question to receive help. This is a forum policy.
Title: Re: Molarity task
Post by: Arkcon on February 18, 2013, 06:03:00 PM
This is a cute question -- I got almost this exact one during my first job interview.  I couldn't solve it.  :(  But I got the job anyway. ;)  That Mr for NaOH, what are the units for that value?  Try to find it, even if the problem doesn't specify the units.  It might help you understand this problem.
Title: Re: Molarity task
Post by: Maciejczyk on February 18, 2013, 06:55:34 PM
Oh, I am sorry, my bad. Here is description:

to determine the number of moles (mol) present or the molar (M or mol/L, moldm-3) concentration, where m is the mass in grams, Mr is the relative molecular mass (the mass of 1 mol of a chemical) and V is the volume in litres (L or dm3). Don’t confuse m, M, Mr and mol they represent different things.

mol =  m/Mr
M = m/( Mr x V)
mol = M x V
Title: Re: Molarity task
Post by: AWK on February 18, 2013, 07:16:23 PM
M = m/( Mr x V)
Hence calculate m.
Title: Re: Molarity task
Post by: Maciejczyk on February 19, 2013, 04:30:19 AM
Thank you!


Is this good result?

M = m/( Mr x V)
M = 0.5/(40 x 0.2)
M = 0.5 / 8 = 0,0625
Title: Re: Molarity task
Post by: sjb on February 19, 2013, 04:44:24 AM
Thank you!


Is this good result?

M = m/( Mr x V)
M = 0.5/(40 x 0.2)
M = 0.5 / 8 = 0,0625

What are your units?
Title: Re: Molarity task
Post by: Maciejczyk on February 19, 2013, 05:06:13 AM
M = m/( Mr x V)

M = 0.5L / (40(?) x 0.2M)
M = 0.5L / 8(?) = 0,0625(?)


Any advises?

Title: Re: Molarity task
Post by: Borek on February 19, 2013, 05:19:22 AM
Assuming Mr is a molar mass, what are units of molar mass?
Title: Re: Molarity task
Post by: Maciejczyk on February 20, 2013, 04:48:05 AM
Mr is the relative molecular mass (the mass of 1 mol of a chemical)
Title: Re: Molarity task
Post by: Borek on February 20, 2013, 05:47:58 AM
Sigh, stop dodging the question.
Title: Re: Molarity task
Post by: Arkcon on February 20, 2013, 07:16:54 AM
Mr is the relative molecular mass (the mass of 1 mol of a chemical)

Awesome.  So, One mole of NaOH weighs 40 ... units?  And once you have that, and you know molarity is moles per liter, and you know the molarity you want, and the volume (given to you as some fraction of a liter), can you then solve it -- keeping the units in pace after each number so you can keep track of everything and we (and your instructor on an exam) can see where you're getting everything?
Title: Re: Molarity task
Post by: Maciejczyk on February 24, 2013, 08:19:52 AM
Please tell me if these are right calculations for this task.
http://s15.postimage.org/4dippo83f/calculation.jpg (http://s15.postimage.org/4dippo83f/calculation.jpg)



Title: Re: Molarity task
Post by: Arkcon on February 24, 2013, 08:29:54 AM
You get the correct answer.  Do you understand the meaning behind the labels on each box?  If you know it well, you'll be better off come examination time.  Or you know, when you actually have to prepare a solution in the laboratory.
Title: Re: Molarity task
Post by: Maciejczyk on February 24, 2013, 08:54:09 AM
Thank you!