May 02, 2024, 07:44:01 PM
Forum Rules: Read This Before Posting


Topic: Substitution/ Elimination reaction  (Read 7820 times)

0 Members and 1 Guest are viewing this topic.

Offline sweetbabu

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Substitution/ Elimination reaction
« on: March 19, 2008, 03:05:10 AM »
Please help me on following question.   :'(

You are planning to carry out a reaction between propyne, CH3C≡CH and sodium amide, NaNH2.  You also need to choose an appropriate solvent for carrying out the reaction.  Would ethanol be suitable for this purpose?  Explain your rationale clearly.

Offline agrobert

  • Chemist
  • Full Member
  • *
  • Posts: 629
  • Mole Snacks: +69/-17
  • Gender: Male
  • diels alder
Re: Substitution/ Elimination reaction
« Reply #1 on: March 19, 2008, 03:12:38 AM »
What do you think?  What do you know about alkyne reactivity/reactions?  Would ethanol interfere with NaNH2?
In the realm of scientific observation, luck is only granted to those who are prepared. -Louis Pasteur

Offline mir

  • Fascinated organic chemist
  • Chemist
  • Full Member
  • *
  • Posts: 310
  • Mole Snacks: +13/-3
  • Gender: Male
  • Visit my blog: mir.humle.be
    • My humble homepage with norwegian articles
Re: Substitution/ Elimination reaction
« Reply #2 on: March 19, 2008, 08:37:40 AM »
And what is it about the -:NH2 ion?
No single thing abides, but all things flow.
Fragment to fragment clings, and thus they grow
Until we know and name them.
Then by degrees they change and are no more
The things we know.
- Titus Lucretius Carus

http://www.ife.no

Offline sweetbabu

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Re: Substitution/ Elimination reaction
« Reply #3 on: March 19, 2008, 06:31:05 PM »
To form an propynylide anion completely with the base, a solvent should be weaker acid than propyne. That will exclude all alcohols.

Just as sodium amide deprotonates the propyne to give ammonia and the sodium salt of the propyne, any solvents that are more acidic than propyne will exchange the proton of the solvent to produce its anion and return propyne anion to propyne.
??? does it sound right???

Offline macman104

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 1644
  • Mole Snacks: +168/-26
  • Gender: Male
Re: Substitution/ Elimination reaction
« Reply #4 on: March 19, 2008, 07:36:37 PM »
Sounds like a pretty good explanation to me.

Offline agrobert

  • Chemist
  • Full Member
  • *
  • Posts: 629
  • Mole Snacks: +69/-17
  • Gender: Male
  • diels alder
Re: Substitution/ Elimination reaction
« Reply #5 on: March 19, 2008, 07:45:20 PM »
To form an propynylide anion completely with the base, a solvent should be weaker acid than propyne. That will exclude all alcohols.

Just as sodium amide deprotonates the propyne to give ammonia and the sodium salt of the propyne, any solvents that are more acidic than propyne will exchange the proton of the solvent to produce its anion and return propyne anion to propyne.
??? does it sound right???


SO, what solvents can you use?  What is common for this reacton?
In the realm of scientific observation, luck is only granted to those who are prepared. -Louis Pasteur

Sponsored Links