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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: astrapw on October 21, 2006, 09:48:39 PM

Title: Equilibria equation
Post by: astrapw on October 21, 2006, 09:48:39 PM

How would you write a balanced equilibria equation for benzoic acid(C5H5COOH) and NaOH?

Thanks

Title: Re: Equilibria equation
Post by: Yggdrasil on October 21, 2006, 09:53:47 PM

What kind of reaction would you expect between benzoic acid and NaOH, a base?

Title: Re: Equilibria equation
Post by: astrapw on October 21, 2006, 10:04:52 PM

A salt???  I would have thought part of the product side to contain water.

Title: Re: Equilibria equation
Post by: Yggdrasil on October 21, 2006, 10:12:11 PM

acid + base --> salt + water

Title: Re: Equilibria equation
Post by: astrapw on October 21, 2006, 10:17:41 PM

I understand the salt + H2O, but still am unsure how to write the equation.

C6H5COOH+NaOH <-----> C6H5COONA+H2O??

Title: Re: Equilibria equation
Post by: Yggdrasil on October 21, 2006, 10:22:23 PM

You know more than you think.  Your answer is correct.

Side note: the C₆H₅COONa is sodium benzoate, a common food preservative.