May 14, 2024, 09:40:59 PM
Forum Rules: Read This Before Posting


Topic: finding equation  (Read 4362 times)

0 Members and 1 Guest are viewing this topic.

Offline ahawk1

  • Regular Member
  • ***
  • Posts: 54
  • Mole Snacks: +0/-0
finding equation
« on: February 04, 2009, 03:02:24 PM »
i am given this problem:
Hydrocarbon mixtures are used as fuels. What mass of CO2(g) is produced by the combustion of 337.9 g of a mixture that is 46.9% CH4 and 53.1% C3H8 by mass?
how do i know wut the equation to this problem is, i know there has to be O2 gas somewhere in this equation.

Offline Astrokel

  • Full Member
  • ****
  • Posts: 989
  • Mole Snacks: +65/-10
  • Gender: Male
Re: finding equation
« Reply #1 on: February 04, 2009, 03:26:53 PM »
Complete combustion of hydrocarbon always produce carbon dioxide and water
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline ahawk1

  • Regular Member
  • ***
  • Posts: 54
  • Mole Snacks: +0/-0
Re: finding equation
« Reply #2 on: February 04, 2009, 05:32:51 PM »
i am given this problem:
Hydrocarbon mixtures are used as fuels. What mass of CO2(g) is produced by the combustion of 337.9 g of a mixture that is 46.9% CH4 and 53.1% C3H8 by mass?
how do i know wut the equation to this problem is, i know there has to be O2 gas somewhere in this equation.
[/quote



so would the unbalanced equation be:
CH4+C3H8+O2=CO2+H2O??

Offline ARGOS++

  • Sr. Member
  • *****
  • Posts: 1489
  • Mole Snacks: +199/-56
  • Gender: Male
Re: finding equation
« Reply #3 on: February 04, 2009, 05:41:44 PM »

Offline ahawk1

  • Regular Member
  • ***
  • Posts: 54
  • Mole Snacks: +0/-0
Re: finding equation
« Reply #4 on: February 04, 2009, 06:50:25 PM »

Offline ARGOS++

  • Sr. Member
  • *****
  • Posts: 1489
  • Mole Snacks: +199/-56
  • Gender: Male
Re: finding equation
« Reply #5 on: February 04, 2009, 06:55:14 PM »

Offline mreff555

  • Regular Member
  • ***
  • Posts: 29
  • Mole Snacks: +0/-0
Re: finding equation
« Reply #6 on: February 04, 2009, 10:14:16 PM »
1. Multiply each percentage by the total mass to get the mass of each compound
2. divide each mass by the the mole weight for each compund. (should be about 10, and 4 mol)
3. balance the equations, add the mole values of CO2 and divide by the mole mass of CO2
Should be around 968g


Sponsored Links