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Topic: I'm stuck on the derivation of the weak acid cubic equation.  (Read 4579 times)

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Offline DutchGirl13

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I'm stuck on the derivation of the weak acid cubic equation.
« on: November 11, 2010, 09:21:03 PM »
I'm given these equations:
HA=CHA-A-
H+=OH-+A-
OH-=Kw/H+
Ka=H+*A-/HA

Using rearrangements of the first three substituted into the last one, I'm supposed to derive 0= H+3+KaH+^2-(Kw+KaCHA)*H+-Kw*Ka.

My final Ka= H+*(H+-(Kw/H+))/(CHA-(H+-(Kw/H+))
This leads to KaCHA-KaKw/H+-KaH+-H+^2+Kw=0,not the cubic. Where am I going wrong in my algebra?
« Last Edit: November 12, 2010, 03:58:40 AM by Borek »

Offline DutchGirl13

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Re: I'm stuck on the derivation of the weak acid cubic equation.
« Reply #1 on: November 11, 2010, 09:23:34 PM »
Oops. I apparently forgot to hit "end'' after doing subscripts, or did something else wrongly.

0= H+3+KaH+^2-(Kw+KaCHA)*H+-Kw*Ka.

My final Ka= H+*(H+-(Kw/H+))/(CHA-(H+-(Kw/H+))
This leads to KaCHA-KaKw/H+-KaH+-H+^2+Kw=0, not the cubic. Where am I going wrong in my algebra?

Offline AWK

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Re: I'm stuck on the derivation of the weak acid cubic equation.
« Reply #2 on: November 12, 2010, 01:30:10 AM »
One set of brackets missing
Ka= (H+*(H+-(Kw/H+)))/(CHA-(H+-(Kw/H+))
AWK

Offline Borek

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Re: I'm stuck on the derivation of the weak acid cubic equation.
« Reply #3 on: November 12, 2010, 04:00:47 AM »
One set of brackets missing
Ka= (H+*(H+-(Kw/H+)))/(CHA-(H+-(Kw/H+))

It doesn't change anything, x*y/z is not different from (x*y)/x  ;D

That's what happens when you list H+ instead of H+ or [H+] or [H+] or just H.

« Last Edit: November 12, 2010, 06:44:45 AM by AWK »
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Offline AWK

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Re: I'm stuck on the derivation of the weak acid cubic equation.
« Reply #4 on: November 12, 2010, 06:44:07 AM »
My correction of formula slightly improve its correct understanding (assuming "H+" always means concentration of H+).

Sorry,
something goes wrong on the forum (may be my fault) and instead of quoting I edited Borek  post.
Moreower, a  multiplication in nominator  (dot) is visible here as short minus sign
should be read as  [H3O+]*([H3O+]-Kw/[H3O+])
« Last Edit: November 12, 2010, 07:02:11 AM by AWK »
AWK

Offline Borek

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Re: I'm stuck on the derivation of the weak acid cubic equation.
« Reply #5 on: November 12, 2010, 08:33:12 AM »
Strange, looks like one of my posts disappeared.

My final Ka= H+*(H+-(Kw/H+))/(CHA-(H+-(Kw/H+))
This leads to KaCHA-KaKw/H+-KaH+-H+^2+Kw=0,not the cubic. Where am I going wrong in my algebra?

Hard to tell what you did wrong not seeing your algebra.

Ka= H+*(H+-(Kw/H+))/(CHA-(H+-(Kw/H+)) looks to me like already 3rd degree equation.
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