good,
Write down what you know so far, it would be good to make a little table of what you started with, what reacts, what's left over
H2S04 + Pb(C2H3O2)2 = PbSO4 + 2H(C2H3O2)
Reactants:
10g Pb(C2H3O2)2 gets used up - 0 grams after rxn
10 g H2SO4 - if its not used up, there is some left over.
a) to find Left over: do a similar calculation as before starting with 10g Pb(C2H3O2)2 to find how much H2SO4 will be used at the same time.
b) then 10g H2SO4 starting amt - H2SO4 used up = left over H2SO4
Products:
PbSO4 - 9.31 g already calculated
HC2H3O2: pls recheck your calculation, remember it is 2 HC2H2O2 : 1 Pb(C2H3O2)2 ratio
keep going, you'll get there