Chemical Forums

Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: sugars22 on March 07, 2011, 05:27:23 PM

Title: oxidation reaction of benzaldoxime by (NaOCl)
Post by: sugars22 on March 07, 2011, 05:27:23 PM

I need help with the reaction mechanism for the oxidation of benzaldoxime by NaOCl. I am suppose to treat the NaOCl as NaOH and Cl₂(g).

so I start with Ph-CH=N-OH (benzaldoxime) but I am not sure how the chlorine gas attack or how the reaction attacks the chlorine gas (Cl₂) Because I am suppose to form this chloro-oxime intermediate (below):
  (Ph-C= N-OH) the Cl is attached to the C
        l
       Cl
Also which attacks first the NaOH attack- please explain to me