Could I use the (inverse)combustion reaction for ethylene?
2CO2 + 2H2O -----> C2H4 + 3O2
In that case, I would use 2000 mol for ethylene, resulting in:
4000CO2 + 4000H2O ----> 2000C2H4 + 6000O2
Then, for the enthalpy of formation, I'd do:
Ef = Ef(products) - Ef(reagents)
This would result in 2820000 kJ/mol.
But I don't think this is the correct answer.
I don't really know how to find the enthalpy of formation of LDPE using the polymerization, although I know the following reaction:
(C2H4=C2H4)n ---> -(C2H4-C2H4)-n
But the problem doesn't offer any values for the break of bonds for carbon. What do I do from here?
Thanks for the help so far.