i hve been having trouble trying to figure out this problem: a solution of 10.00 ml of .750 M Cu(OAc)2, a soluble salt, and 10.00 mL of .150 M HCl are mixed together in a beaker. a reaction occurs and a white solid, CuCl2 (s), precipitates and settles on the bottom of the flask. acetic acid is produced as well. ksp of CuCl2 is 2.0 x 10 ^-9
Write the balanced equation for the reaction of Cu(OAc)2 and HCl and determine the concentrations of:
[Cu+2], [HOAc], [OAc-], and [H3O+]
okay i think i have the balanced equation which is
Cu(OAc)2 + 2HCl ---->>> CuCl2 + 2HOAc
i am just not sure where to go now. i thought i could solve the [Cu2+] by using the Ksp which would be
2.0 x 10 ^ -9 = [Cu2+][Cl]^2
i got 7.94 x 10 ^ -4 M = Cu2+, i am not sure if i am on the right track, any help would be appreciated