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Topic: The value of x in the compound, VClx  (Read 1825 times)

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Offline ktgerloff

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The value of x in the compound, VClx
« on: February 04, 2015, 12:07:54 PM »
Hello,

This problem is from a practice exam from my second term general chemistry class. The correct answer is highlighted in red:

When 1.13 g of V is dissolved in HCl, 0.08888 g of hydrogen gas is produced.  Determine the value of x in the compound, VClx, produced according to the following equation:

V  + xHCl  →  VClx  +  (x/2) H2

a) 1
b) 2
c) 3
d) 4
e) none of these


I see how all of these answers will balance the equation. I must be missing the point of the question here. Can someone please explain what I am missing?
« Last Edit: February 04, 2015, 12:26:25 PM by ktgerloff »

Offline Corribus

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Re: The value of x in the compound, VClx
« Reply #1 on: February 04, 2015, 12:30:38 PM »
There may be many ways to correctly balance the equation, but only one of them will work with the masses of reagents and products provided. A hint is to convert those masses into moles and then consider the stoichiometry.

What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

Offline ktgerloff

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Re: The value of x in the compound, VClx
« Reply #2 on: February 04, 2015, 12:58:07 PM »
I see, so there is 0.022 mol V and 0.044 mol H2.

So, for every 1 mol of V, there must be 2 mol of H2.

Which is where the 4 comes from...

Thanks!

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