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Topic: methylmalonic + naoh reaction  (Read 4007 times)

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panther

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methylmalonic + naoh reaction
« on: November 29, 2005, 03:06:28 PM »
hi,

i have tried this problem for a while but i cannot get it :(

i think the formula for methylmalonic acid is this:
(CH3)2C(CO2H)2

if i react with it sodium hydroxide (NaOH) what will the products be?

please help :| i know H2O is in there, and i swear i have tried. i know it loses a H from this: (CH3)2 C (COOH)

Please help :(


panther

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Re:methylmalonic + naoh reaction
« Reply #1 on: November 29, 2005, 03:12:02 PM »
and i think the ans is this:

(CH3)2 C (COOH) (COO-)Na+

but it's diprotic so how come it only looses 1 H?

Offline Albert

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Re:methylmalonic + naoh reaction
« Reply #2 on: November 29, 2005, 03:45:32 PM »
(CH3)2 C (COOH)2

This is NOT methylmalonic acid.
However, here is your reaction: everything depends on the concentration of NaOH.

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