May 08, 2024, 02:34:58 PM
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Analytical Chemistry Forum / Re: Titration
« Last post by i_am_frustrated on Today at 02:16:26 PM »
Ah I am so thankful for your replies. Really appreciate it
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Chemical Engineering Forum / Re: Engineers: Introduce Yourself
« Last post by mikefot on Today at 01:12:52 PM »
Hello everyone.  I am a scientist with background in biochemistry and PhD in protein engineering in the UK. 
I have done some bioreactor process development R&D in a small company and I attended a course in biochemical engineering in
Switzerland a number of years ago.  I am interested in chemical engineering.
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High School Chemistry Forum / Re: Termodynamics Mechanical Equilibrium
« Last post by Borek on Today at 01:09:03 PM »
Will there be change in volume, or only in pressure? Question doesn't state if tanks are rigid or not.
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High School Chemistry Forum / Re: Termodynamics Mechanical Equilibrium
« Last post by less_345 on Today at 09:55:22 AM »
subsystems have the same temperature (300 K), pressure (10e5 Pa), and volume (0.05 m3 each subsystem), but subsystem A has 1.5 mol of H2 and B 1 mol of He

You can't have two subsystems with the same PVT and different number of moles.

(Besides, neither 1 nor 1.5 moles fits given PVT data)


Thank you, in a previous step the wall changed from adiabatic to diathermic, thus the thermal equilibrium was reached, thus I made a mistake considering that the pressure will remain the same after that change as it was already in equilibrium, but I just realized that it was not the caseā€¦
In this case the change in volume will be due to the equilibrium in pressure, this change will produce a dS=0 since there is no change in heat/temperature and the process is reversible, am I right?
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Can you show us what you tried so far?
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Good Afternoon Everyone

I'm a 3rd year chemical engineering student currently I have a problem in process design for ammonia stripping process I'm using crystallisation to crystallize  at this crystallisation process from some papers  the operation temperature is at the range of 50-140 degrees Celsius but in my case when I'll try to input the temperature 60degree Celsius the results became superheated does anyone can give me some insight why is this happened

Thank you so much for reading my post
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High School Chemistry Forum / Re: Termodynamics Mechanical Equilibrium
« Last post by Borek on Today at 02:59:32 AM »
subsystems have the same temperature (300 K), pressure (10e5 Pa), and volume (0.05 m3 each subsystem), but subsystem A has 1.5 mol of H2 and B 1 mol of He

You can't have two subsystems with the same PVT and different number of moles.

(Besides, neither 1 nor 1.5 moles fits given PVT data)
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High School Chemistry Forum / Termodynamics Mechanical Equilibrium
« Last post by less_345 on Yesterday at 11:44:08 PM »
I have a question with the following question:
1) Consider 1 system divided into two subsystems (A and B) separated by a diathermic, immobile, and impermeable wall, the subsystems have the same temperature (300 K), pressure (10e5 Pa), and volume (0.05 m3 each subsystem), but subsystem A has 1.5 mol of H2 and B 1 mol of He. If the wall becomes diathermic, flexible and impermeable, will there be a change in volume of the subsystems?

I'm not sure if the system will change to a new Teq due to the expansion of the subsystem with 1.5 mol of H2, or since the system is already in equilibrium, there will be no change of T nor of P, and thus, the volume will remain the same...

On the other hand, in case the volume is changed, should the change of entropy be calculated by the equation dS= nARln(V2A/V1A) + nBRln(V2B/V1B)?

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Organic Chemistry Forum / Re: Is Two-pentene also called isopentene?
« Last post by mjc123 on Yesterday at 03:39:49 PM »
There is no "rule" about a "middle carbon". It just happens in your example that there is a distinction between the terminal carbons (removing H from which gives n-propyl) and the middle one - the sole non-terminal carbon. For molecules with more than one non-terminal C, there is no rule about the middle one giving iso. In fact, apart from isopropyl, iso- names are derived from isoalkanes, which are branched. Thus isobutene is 2-methylpropene (not 2-butene). Isopentene is 3-methyl-1-pentene (why that rather than any other derivative of isopentane, I'm not sure; perhaps the honour goes to the least substituted alkene?). 2-pentene is not isopentene.
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Analytical Chemistry Forum / Re: Titration
« Last post by Borek on Yesterday at 03:04:25 PM »
Worth to remember high titrant concentration means better detection of the endpoint, but worse accuracy (error reading burette for lower titrant volume means higher percent error).

Matter of finding a sweet spot, with good endpoint detection, but titrant volume around 80% of the burette volume.
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