Is this right?
A 15.5g of chromium, heated to 100 ºC is dropped into 55.5g H2O at 16.5 ºC. The final temp. of the metal and H2O is 18.9 ºC. What is the specific heat capacity of the chromium?
(M1C1∆T2) = - (M2C2∆T2)
[15.5g Cr *? * -81.1 K] = [55.5g H2O * 4.184 * 195.05 K] - [55.5g H2O * 4.184 * 275.55 K] / [15.5g * 195.05 K] =
- 63986.02 / 2976.78 =
-21.50 J / g ºK