[4evrastudent]

I'm asked to find the [itex]K_{eq}[/itex] of [tex]As_4O_6(s) + 6H_2O(l) \rightleftharpoons 4H_3AsO_3(aq)[/tex]

To my knowledge, pure liquids are not put into equilibrium constants, and neither are solids. However, this would lead me to believe that nothing would go into the denominator of my equilibrium constant. In other words, I would put zero into the denominator. This doesn't make sense to me. Am I mistaken in saying both solids and pure liquids are excluded form equilibrium constants? Do I just put the number 1 into the denominator? Thanks!

Sorry for formatting issues; I'm new to LaTeX.

Edit: corrected

[curiouscat]

Yes. 1 not 0.