Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: student8607 on November 23, 2008, 01:47:56 PM
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This past week I did a chemistry lab that tested the freezing point of different solutes in water.
Sucrose: C12H22O11(s) + H2O(l) -->
Glucose: C6H12O6(s) + H2O(l) -->
Di-alcohol: C2H4(OH)2(aq) + H2O(l) -->
Tri-alcohol: C3H5(OH)3(aq)+ H2O(l) -->
I'm just not sure how to finish writing these "dissolution of the solid into water" equations?? Do I just group everything together like (C12H24O12) for sucrose?
I also wasn't sure if di-alcohol and tri-alcohol would classify as liquids or aqueous solutions?
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X(aq) means that it is already in aqueous (water) solution. X(l) means that it is a liquid. Can you think of some other liquids that you may have come across that are not water?
You should not just group everything together like C12H24O12 unless you are sure you are creating a new substance...
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OK, well then the alcohols are definitely in aqueous form.
No, no new substance was formed. They were just mixed together???