[sciencenoob85]

So my understand when titrating and acid and base I can use the data from the known substance to calculate the concentration of the unknown

My calculation feel a little short

Have I missed anything? or is it just wrong?

The number of mols present in the titre of the known substance can be used to determine the concentration of the unknown acid.

NaOH:   n=vm
   n= 25.00 cm3 x 1.0 mol
   n= 25.00 moldm3/1000
   n= 0.025 moldm3

                      CH3COOH(aq) + NaOH(aq)         CH3COONa(aq) + H2O(l)

CH3COOH:
   n= 0.025 moldm3

Using mols and volume it is possible to work out the concentration;

   c=m/v
   c= 24.10 cm3/0.025mol
   c= 964moldm3/1000
   c= 0.964moldm3

Thanks for the advice

[mjc123]

NaOH:   n=vm
   n= 25.00 cm3 x 1.0 mol
   n= 25.00 moldm3/1000
   n= 0.025 moldm3

Your units are all over the place
n = 25 cm³ x 1.0 mol/dm³ (I presume)
n = 0.025 dm³ x 1.0 mol/dm³
n = 0.025 mol

NaOH reacts with AcOH in a 1:1 molar ratio, so at the end point you have 0.025 mol AcOH. I presume 24.10 cm³ is the volume of AcOH solution at the end point.

c=m/v

You have already used m for molar concentration, and n for moles. Be consistent. c = m = n/v

c= 24.10 cm3/0.025mol

Why are you dividing volume by moles? c = n/v = 0.025 mol/24.10 cm³
Proceed from here, and get the units right.