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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: kk914 on February 28, 2021, 08:59:00 PM

Title: How many moles are in 326.19 g of FeBr?
Post by: kk914 on February 28, 2021, 08:59:00 PM

Can someone explain how you got the solution and show all work.

Title: Re: How many moles are in 326.19 g of FeBr?
Post by: billnotgatez on February 28, 2021, 09:27:15 PM

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Title: Re: How many moles are in 326.19 g of FeBr?
Post by: billnotgatez on February 28, 2021, 09:33:43 PM

Quote from: kk914 on February 28, 2021, 08:59:00 PM

Can someone explain how you got the solution and show all work.

Which one
Iron(II) bromide, ferrous bromide    FeBr₂
Iron(III) bromide, ferric bromide      FeBr₃

Title: Re: How many moles are in 326.19 g of FeBr?
Post by: Vidya on March 01, 2021, 12:59:02 AM

First check the correct formula --
Now convert grams to moles using molar mass.
1 moles of a compound  mass equal to its molar mass.
Like H2O molecule
1 mole of H2O = 18.00 g

Title: Re: How many moles are in 326.19 g of FeBr?
Post by: NotCitricAcid on March 01, 2021, 08:56:18 PM

moles = mass / molar mass

moles = 326.19 / 295.56

moles = 1.10363378..

Title: Re: How many moles are in 326.19 g of FeBr?
Post by: AWK on March 01, 2021, 11:23:51 PM

This is the calculation for FeBr3. It still remains to determine the number of significant figures.