Consider a buffer consisting of 0.75 M NH3 and 0.50 M NH4Cl. If 0.10 M H2SO4 is added to the solution with no change in volume, what is the resulting pH?
I'm not certain how to go about this one. The pkb oh NH3 isn't on the tables provided. Ammonia's pka is given (36) , but I'm not sure on how to use that. I know pOH = pKb + log (b+/boh). I assume I need this formula to find the initial pH, but I'm not sure. Thanks.