Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: orgo814 on April 28, 2013, 06:15:38 PM
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Can someone make sure I'm correct and clear up any areas of confusion in this question? I'll show you my reasoning
Which of the following are chelating ligands? a) PO4(3-) b) Si2O7(6-) c) CH3-O-CH2-O-CH3 d) (CH3)3N e) N(CH2-CO2-)3 f) [NH3CH2CH2NH3]2+
For (A)- I'm pretty sure that this is not a chelating ligand since although there are oxygen atoms that have electrons to donate they are too close to one another to chelate
For (B)- I know the structure has one oxygen bridging the two silicon atoms... Again, I think the oxygen atoms are two close to chelate but I could be wrong for this one
For (C)- It only has one -CH2 group between the two potential donor atoms (oxygen) and the book says that there should be at least two or 3 so I determined this one to not be a chelating ligand
For (D)- This one was obvious- only one nitrogen atom so it is not
For (E)- This was one is a chelating ligand since there is the nitrogen atom and the oxygen atoms which are far enough apart from eachother
For (F)- This was one was obvious that it is not a chelating ligand (no electrons to donate!)
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You should draw the structures. I agree mostly. But in e, the molecule is called triethylamine and if you draw the molecule you will see it is not a chelating ligand. you will see it is not different than the molecule in d. In b, the molecule is 6- charged and it is clearly a chelating ligand. Draw the structure and you will see.
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You should draw the structures. I agree mostly. But in e, the molecule is called triethylamine and if you draw the molecule you will see it is not a chelating ligand. you will see it is not different than the molecule in d. In b, the molecule is 6- charged and it is clearly a chelating ligand. Draw the structure and you will see.
e is not triethylamine - don't forget the carboxylates.
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I did draw the structures and I disagree about E. there are three negatively charged oxygen atoms from each of those groups along with that nitrogen. Therefore, I reason it to be a chelating ligand
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You should draw the structures. I agree mostly. But in e, the molecule is called triethylamine and if you draw the molecule you will see it is not a chelating ligand. you will see it is not different than the molecule in d. In b, the molecule is 6- charged and it is clearly a chelating ligand. Draw the structure and you will see.
e is not triethylamine - don't forget the carboxylates.
sorry :) I wasn't really paying attention and I made a big mistake. Thanks for correcting.