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Topic: Organic Chemistry Equations  (Read 3579 times)

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Offline Marco

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Organic Chemistry Equations
« on: January 31, 2010, 11:50:06 AM »
May anyone have a look at these equations? They deal with an experiment in order to identify which of the four compounds labelled A, B C, D is a Primary Alcohol, an Aldehyde, a Ketone or a Carboxylic Acid.
1) The equation of the reaction when sodium carbonate was poured in the compound B where a dilute carboxylic acid was identified:

2CH3COOH(aq) + Na2CO3(aq) → 2CH3COONa(aq) + H2O(l) + CO2(g)
IS THIS CORRECT ?

2) The equation of the reaction when Fehling's solutions A and B were poured in the compound C where an aldehyde was identified:

RCOH(aq) + 2CuO(aq) + 2OH-(aq) → RCOOH(aq) + Cu2O(s) + H2O(l).
IS THIS CORRECT ?

3)The equation of the reaction when acidified sodium dichromate was poured in the compound A where a primary alcohol was identified:

3CH3CHO(aq) + Na2Cr2O72-(aq) + 8H+(aq) → 3CH3COOH(aq) + 2Cr3+(aq) + 4H2O(l)
IS THIS CORRECT ?

Many thanks!

Offline lazipeter

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Re: Organic Chemistry Equations
« Reply #1 on: February 06, 2010, 10:56:59 AM »
Q1 should be correct
For Q2, Fehling's solution contains CuSO4, NaOH and sodium tartrate
So it should'd be CuO, it should be Cu2+
The reaction is :
RCOH(aq) + 2Cu2+(aq) + 5OH-(aq) → RCOO-(aq) + Cu2O(s) + 3H2O(l).

For Q3, Why NaCr2O7 still bear the 2- charge? it is neutral as it is an ionic compound with 2 Na+ and one doubly negatively charged Cr2O72-!
so the reaction should be like this:
3CH3CHO + Cr2O72- + 8H+ ----> 3CH3COOH + 2Cr3+ +4H2O

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