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Topic: Molecular orbital electron configuration  (Read 2470 times)

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Offline orgohell

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Molecular orbital electron configuration
« on: June 20, 2012, 03:20:41 AM »
Hey, I'm having trouble understanding why the electron configuration is different between C2 and O2, as in why is the 2sσ lower in energy then 2pi in one, but is the opposite in the other? How would I know how to set up the configuration if it was say CO?
« Last Edit: June 20, 2012, 03:31:38 AM by orgohell »

Offline cheese (MSW)

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Re: Molecular orbital electron configuration
« Reply #1 on: June 23, 2012, 01:07:09 PM »
Zeff on the 2s electron increases more rapidly than Zeff on the 2p electron because the 2s penetrates the core 1s2 AOs more effectively than the 2p electrons and experiences a larger nuclear charge.  As a consequence the 2s/2p energy gap gets larger going from Li → F.  It is estimated that the 2s-2p energy gap is ~200 kJ mol-1 at Li and increases to ~2500 kJ mol-1 at F.
Because of the large sp energy gap the 2s AO overlap on atom A with the 2pz AO on atom B is not significant and can be ignored for O2 (and its various ions) and F2. Thus we have the simple MO diagram with no sp mixing, e.g., for O2:
O2 = 12 valence e⁻ = σs(2e⁻) σs*(2e⁻) σp(2e⁻) πp(4e⁻) πp*(2e⁻) σp*(0)   
For elements of the first row that are to the left of oxygen in the periodic table the 2s-2p energy gap is smaller.  For this reason the overlap of the 2s AO on one atom with the 2p orbital on the other atom becomes significant. This is called s-p mixing.  The effect of this interaction is typical for AO overlaps:  the two lower energy σ MOs are further lowered in energy and the two higher energy σ MOs are raised in energy.  Of importance is that the third σ3 MO (originally σp) is raised above the π1 MO.  Because the σ MOs have both s and p character and the subscripts are changed to numbers (σ1 – σ4).  For example, the MO diagram for CO (and NO) is:
CO: 10 valence e-  σ1(2e-) σ2 (2e-) π1(4e-) σ3(2e-)      π2*(0e-) σ4*(0e-)
It is crucial in the understanding of bonding of CO to TM (as Ni(CO)4) that the HOMO is a σ MO.
The Schrödinger Wave Equation explains it all.
 


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