Hey Guys, I need help with this question>
When 10.0 L of a saturated solution of magnesium carbonate, MgCO3 , is evaporated to dryness, 0.012g of solid magnesium carbonate is obtained. Calculate the Ksp of magnesium carbonate.
Ok, I've tried everything, and I still could not get the answer (it is 2.0 x 10-10) .
This is what I've done.
The equation I made is : MgCO3 <---> Mg 2+ + CO32-
1.00g MgCO3 x 1 mol MgCO3 / 84.3 g/mol = 0.01168 M / 10 L = 1.87 x 10-3
Ice Table:
I (ignored) 0 0
C (ignored) + x +x
E 1.86 x 10-3 +x +x
Ksp = [Mg][CO3]
I Have no idea what to do next :/ , how can I get the Ksp I am stuck.