[revolve]

K₂Cr₂O₇ + Na₂SO₃ + HCl   → KCl + Na₂SO₄ + CrCl₃ + H₂O

I've gotten to the point where I've found that the reduction is the Cr and the oxidation is the S.
Using the half equation method how am I supposed to proceed? Do I then split these compounds up into ions? Such as:

reduction: Cr₂O₇^2- → Cr³⁺

oxidation: SO₃^2- → SO₄^2-

Would these be the two half equations?

[LQ43]

Yes. Keep going 




Do you know the steps of solving the half reactions?