May 25, 2024, 07:09:34 PM
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Analytical Chemistry Forum / Re: Kinetic chain reaction mechanism
« Last post by Hunter2 on Today at 04:08:33 PM »
It's because two reactions take place which create CH4.

The System is feed with C2H6 and H2

C2H6 will be cracked in two CH3° radicals.

This react with hydrogen according
CH3° + H2 => CH4 + H°
1. Methane source and a hydrogen radical
And H° react again with ethane according
C2H6 + H° => CH4 + CH3°
2. Methane source and again a methyl radical

Then the game starts again until all Ethane and hydrogen is consumed or the Termination reaction takes place.


2
Analytical Chemistry Forum / Re: Kinetic chain reaction mechanism
« Last post by Linh_ on Today at 03:24:55 PM »
Why is it possible to separate the expression for CH4 to 2 different expressions?
Shouldn't it be one that depends on both reactions?
3
Many thanks for your response! I will look into what you are describing. My tank was held vertically by two clamps, maybe the glass broke from the tension of the clamps and the fact that it happened after I turned the voltage off is just a coincidence?
4
Analytical Chemistry Forum / Re: Kinetic chain reaction mechanism
« Last post by Hunter2 on Today at 12:46:50 PM »
No , you should not add, you should substitute.

CH4 = k2*CH3°*H2/H°

CH4 = k3*C2H6*H°/CH3°

H° = CH4*CH3°/(k3*C2H6)

Fill in this  for H° in first equation.

Solve for CH4 .


5
The failure after the battery being turned off could just be a matter of kinetics. Under Borek's theory of corrosion, corrosive substances generated during the cell operation could take some time to cause enough damage to reach the point of failure.
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Analytical Chemistry Forum / Re: Kinetic chain reaction mechanism
« Last post by Linh_ on Today at 08:56:40 AM »
First is CH4 = k2*CH3°*H2/H° and CH4 = k3*C2H6*H°/CH3° ?
CH4 = k2*CH3°*H2 + k3*C2H6*H°, from the two propagation reactions.
Also the suggested mechanism is part of the question and not something I chose.

Can you explain more please? substituting here doesn't lead to anything and I don't know what to do
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Analytical Chemistry Forum / Re: Kinetic chain reaction mechanism
« Last post by Hunter2 on Today at 07:56:21 AM »
First is CH4 = k2*CH3°*H2/H° and CH4 = k3*C2H6*H°/CH3° ?

Only this two equations have to be combined.
Substitute H° in first equation with second equation and solve for CH4.

Initiation and Termination is in my opinion not necessary. It's not part of the chain reaction.
Termination have more possibilities like 2 H° => H2 or CH3° + H° => CH4



8
Analytical Chemistry Forum / Kinetic chain reaction mechanism
« Last post by Linh_ on Today at 07:15:54 AM »
this is the question and the beginning of my answer
https://imgur.com/a/Xw0AM7I

I just don't know what to do from here, I tried substituting but it doesn't help and I don't have any other idea.
Can someone help me please?
9
Thank you again for the response, it seems very weird that this happened especially after turning the voltage off.
10
Three factors that could contribute to the failure: hydrogen, chlorine, and pH going up. Hydrogen seems to be the least problematic, but both chlorine and high pH can easily speed up corrosion/decomposition of many substances/glues.

Doesn't mean it wasn't just a completely random thing.
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