my attempts:
CH3COONa + HCl = CH3COOH + NaCl
pHi = 5 = pKa + log(CH3COONa/ CH3COOH)
pHf = 4 = pka + log (CH3COONa f / CH3COOH f) ( by the adding of HCl)
C CH3COONa f = C CH3COONa x v - (0.5Ma x 100ml) / vt
C CH3COOH f = C CH3COOH x v + (0.5Ma x 100ml) / vt