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Topic: k and K  (Read 8198 times)

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Offline mir

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k and K
« on: May 18, 2006, 01:08:38 PM »
Is there any equation that connects the rate constant and equilibrium constant?
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Offline Borek

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Re: k and K
« Reply #1 on: May 18, 2006, 01:57:11 PM »
No.
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Offline mir

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Re: k and K
« Reply #2 on: May 18, 2006, 03:30:59 PM »
Maybe something for me to find out sometime...  :)
No single thing abides, but all things flow.
Fragment to fragment clings, and thus they grow
Until we know and name them.
Then by degrees they change and are no more
The things we know.
- Titus Lucretius Carus

http://www.ife.no

Offline Yggdrasil

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Re: k and K
« Reply #3 on: May 18, 2006, 08:51:39 PM »
If k1 is the forward rate constant and k -1 is the reverse rate constant, isn't the equilibrium constant just K = k1/k -1?

Offline Borek

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Re: k and K
« Reply #4 on: May 19, 2006, 03:36:14 AM »
If k1 is the forward rate constant and k -1 is the reverse rate constant, isn't the equilibrium constant just K = k1/k -1?

It is, but that's when you know both k. As long as you know one only - you are out of luck.
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Offline mir

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Re: k and K
« Reply #5 on: May 19, 2006, 06:24:43 AM »
If k1 is the forward rate constant and k -1 is the reverse rate constant, isn't the equilibrium constant just K = k1/k -1?

Well I was hoping to find such an expression somewhere. Thank you :-)

Curious that I havent seen it before...
No single thing abides, but all things flow.
Fragment to fragment clings, and thus they grow
Until we know and name them.
Then by degrees they change and are no more
The things we know.
- Titus Lucretius Carus

http://www.ife.no

Offline Donaldson Tan

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Re: k and K
« Reply #6 on: May 20, 2006, 10:44:18 AM »
consider the chemical equilibrium A <-> B

forward rate = k1CA
backward rate = k2CB

at dynamic equilibrium, forward rate = backward rate
k1CA = k2CB
K = CB/CA = k1/k2
« Last Edit: May 20, 2006, 10:46:01 AM by geodome »
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Offline edwinksl

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Re: k and K
« Reply #7 on: May 28, 2006, 01:21:45 AM »
If k1 is the forward rate constant and k -1 is the reverse rate constant, isn't the equilibrium constant just K = k1/k -1?

Well I was hoping to find such an expression somewhere. Thank you :-)

Curious that I havent seen it before...

I thought you learn this in high school under chemical equilibrium?

Offline mir

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Re: k and K
« Reply #8 on: May 28, 2006, 05:53:26 AM »
I thought you learn this in high school under chemical equilibrium?

Learning isnt a linear process.
No single thing abides, but all things flow.
Fragment to fragment clings, and thus they grow
Until we know and name them.
Then by degrees they change and are no more
The things we know.
- Titus Lucretius Carus

http://www.ife.no

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