May 11, 2024, 07:20:46 PM
Forum Rules: Read This Before Posting


Topic: Acids and bases  (Read 3213 times)

0 Members and 1 Guest are viewing this topic.

Offline Minerva Scriptor

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Acids and bases
« on: May 06, 2009, 01:04:23 AM »
Being in honors Chemistry, I was intelligent enough to leave my notes at school, and now have to figure out how to finish my homework through the internet. 

Anyway, I need to predict the acidic or basic nature of several different anhydrides (CaO, CO2, Na2O, NO, SO3, and Rb2O)
I have a feeling this is pretty simple, but I have know idea how it is done.

For another question, I have to find the pH, pOH, (H+), and (OH-) of .00015 M HNO3.
I came up with

(H+) = .00015
pH = 3.82
pOH = 10.18
(OH-) = 6.607x10^-11

Is this correct?  it seems too easy.

Offline Rabn

  • Chemist
  • Full Member
  • *
  • Posts: 284
  • Mole Snacks: +28/-13
Re: Acids and bases
« Reply #1 on: May 06, 2009, 01:30:46 AM »
Have you considered equilibrium?

Offline Minerva Scriptor

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Re: Acids and bases
« Reply #2 on: May 06, 2009, 01:35:01 AM »
No, do you think I should? 

Never mind, I'm pretty sure my teacher mentioned we wouldn't be including equilibrium until next week.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27676
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Acids and bases
« Reply #3 on: May 06, 2009, 03:29:36 AM »
Anyway, I need to predict the acidic or basic nature of several different anhydrides (CaO, CO2, Na2O, NO, SO3, and Rb2O)
I have a feeling this is pretty simple, but I have know idea how it is done.

Try to write reaction equations for all thes substances with water.

Quote
For another question, I have to find the pH, pOH, (H+), and (OH-) of .00015 M HNO3.
I came up with

(H+) = .00015
pH = 3.82
pOH = 10.18
(OH-) = 6.607x10^-11

Is this correct?  it seems too easy.

Almost OK. Even taking equilibrium into account won't change this result much, solution is so diluted HNO3 is completely dissociated. Two things: you sure it is not 6.667 in the last number? And remember about correct number of significant figures in your answers.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links