hi:
Thanks for the help on the last question. I am stumped on the following question-i think maybe there's a typo in the acs test book.
question:
What is standard enthalpy change for this reaction:
3H2(g) + O3(g) > 3H2O(l)
given:
1) H2(g) + 1/2 O2(g) > H2O(l) = -286kJ
2) 3O2(g) > 2 O3(g) = +271kJ
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The acs book i am using calculates the answer to be -944 kJ.
I calculate -722kJ- which is one of the answer options - but not the correct answer according to the key.
I understand how the book came to -944kJ, but isn't the 2 equation
" 3O2(g) > 2 O3(g) = +271kJ"
suppose to be reversed - as O3(g) is on the products side of the equation that I'm trying to determing the standard enthalpy change = 3H2(g) + O3(g) > 3H2O(l) and there for the +271kJ should be switched to -271kJ.
Thanks for the help. I appreciate it.