When the molecule undergoes hydration reaction in 2 different manners, as seen in the reaction scheme, I know that there will be stereoisomers formed.
However, I am having trouble determining whether the product(s) would be optically active. At first, I concluded that they are both optically active, but I am starting to doubt that.
For the reaction above, the addition of OH and H is anti, and we get a R,S and R,R product. They are diastereomers, so I don't think there will be any optical activity, because the "S" and "R" part for the OH cancels out each other.
For the reaction below, there is only one chiral center, and both products are the same configuration, thus its not optically active.
I am not too sure about my answer, so please point out any conceptual mistakes I have made, if any!