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Topic: Stoichiometry check  (Read 4455 times)

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Offline nate2612

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Stoichiometry check
« on: February 27, 2008, 11:23:56 PM »
When NaI is added to a solution of Cu(NO3)2 the following reaction occurs:

2NaI + Cu(NO3)2 = CuI2 + 2NaNO3

If a chemist needes to make 350.0 g of CuI2, how many mL of 3.3M solution of NaI must be used?
assume that there is excess copper (II) nitrate.


this is my thinking...
the ratio is a 2-1
I have 1.103 moles of CuI2 meaning i have 317.3 amu or 317.3 g
since the ratio is 2-1 I have 2.206 moles of NaI.

(2.206mol divided by 1) x ( 1L divided by 3.3 Moles) = .669L or 669 mL
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Offline AWK

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Re: Stoichiometry check
« Reply #1 on: February 28, 2008, 12:58:04 AM »
2NaI + Cu(NO3)2 = CuI2 + 2NaNO3
this reaction is accompanied by the next and very fast one.
2CuI2 = 2CuI + I2

Hence chemist never have CuI2 in his hands.
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Offline nate2612

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Re: Stoichiometry check
« Reply #2 on: February 28, 2008, 01:04:02 AM »
Why would decomposition be part of this reaction?
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Offline AWK

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Re: Stoichiometry check
« Reply #3 on: February 28, 2008, 01:46:33 AM »
CuI2 is extremely unstable
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