[ByShine]

Sn2+(aq) + 8 H2O(l) <-> 4 H3O+ (aq) + Sn(OH)4^2-(aq)

Sn2+(aq) + 2 Cl-(aq) <-> SnCl2(s)

Adding KOH(aq) to a solution of Sn2+(aq) [both]
will decrease [H3O+] and [Sn(OH)4^2-]

when NaCl(aq) is added, [Sn2+] will decrease, [Sn(OH)4^2-] will decrease and ph will increase

anyone know why?
i been trying to figure out why for the last hour and could not  do so..

[Borek]

What happens when you add Cl^- to the solution? Look at your reactions.

[ByShine]

shifts right?

[Borek]

Second shifts right. What does it mean for Sn²⁺ concentration?

Now take a look at first.

[ByShine]

ok it will shift left for the first reaction, i understand it now and ph will increase since less hydronium ions are being made

but what about when u add koh

[Borek]

Your first reaction can be written either as reaction of tin with water (yielding H⁺), or as reaction of Sn²⁺ with OH^-.