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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: beethove on November 18, 2014, 09:51:10 PM

Title: Density problem
Post by: beethove on November 18, 2014, 09:51:10 PM
At 136°C and atmospheric pressure, the density of TiCl4 is 5.6 g L-1. Under the same conditions, the density of gaseous N is 0.83 g L-1. Determine the molecular formula of TiCl4.

ANSWER: TiCl4

How? And the reasoning?  Thanks!
Title: Re: Density problem
Post by: Hunter2 on November 19, 2014, 01:02:38 AM
Express the density by using ideal gas equation. Calculate molecular mass with it.
Title: Re: Density problem
Post by: mjc123 on November 19, 2014, 04:47:41 AM
And remember that gaseous nitrogen is N2, not N!
Title: Re: Density problem
Post by: beethove on November 19, 2014, 07:07:38 AM
I did and the mole ratio is 1:1, which I guess is why the answer is TiCl4...but why do I even need to know the mole ratio between them figure out the molecular formula TiCl4?
Title: Re: Density problem
Post by: Hunter2 on November 19, 2014, 07:24:57 AM
What mole ratio do you mean.

Confirm the molare mass from N2

You have pV = nRT, n =m/M and Rho = m/V

convert this to M =?

The same you do with the Titanium chloride. The calculated molar mass you have to split in x Ti and y Cl-.
Title: Re: Density problem
Post by: beethove on November 19, 2014, 09:21:51 AM
I just got it.  Your method works.  Another way (and I think what the chapter was trying to test) was that density is proportional to molar mass. So, this also solves it:

5.6 g L-1/0.83 g L-1(28.0 molar mass N2) = 189g of TiCl4

Therefore, TiCl4 is molecular formula.



Title: Re: Density problem
Post by: Hunter2 on November 19, 2014, 09:30:18 AM
Yes correctly.
Title: Re: Density problem
Post by: Borek on November 19, 2014, 09:57:23 AM
Another way (and I think what the chapter was trying to test) was that density is proportional to molar mass.

Both approaches are perfectly equivalent and based on the same basic principles.