Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Superskillzz on April 11, 2011, 07:30:21 PM
-
I'm having trouble figuring out this buffer solution problem...
A buffer is prepared by combining 250 mL of 0.3 M NaOH and 250 mL of a 0.8 M weak acid, HA. If the pH of the buffer is 8.44, what is the Ka of the acid?
-
What exactly are you having trouble with?
-
Ok, well I'm guessing I have to use the Henderson-Hasselblach equation because of the information I'm given and I have to solve for pKa from the equation. So the equation is going to be...
8.44 = pKa + log([conjugate base]/[acid])
I'm having trouble figuring out what values should be used for the conjugate base and acid concentrations. I know you use the NaOH and HA somehow, but that's where I'm stuck.
-
What happens when you add NaOH to HA?
-
Well, an acid plus a base gives a salt and water...so in this case, it would be the salt NaA and water, right?
-
Now do stoichiometry of this reaction.