[tanne]

I'm stuck on this problem:

A scuba diver creates a spherical bubble with a radius of 2.0 cm at a depth of 30.0 m where the total pressure (including atmospheric pressure) is 4.00 atm .

What is the radius of the bubble when it reaches the surface of the water? (Assume atmospheric pressure to be 1.00 atm and the temperature to be 298 K.)

I'm using the equation for the volume of a sphere: V = 4/3*pi*r³

V = 4/3*pi*(2.0cm)³

V = 33.51cm³

   = 0.03351L

And since P1V1 = P2V2...I've solved for V2...

(4.00atm)(0.0335L) = (1.00atm)(V2)

0.134 = V2

Now here is where things go all wrong.

When I use this in the volume equation I get r=0.3175 but this is wrong. Any ideas?

Thanks!

[opti384]

Maybe you could have mistaken the units.

[tanne]

The units need to be cm...I'm kind of lost on what units I ended up with.

[opti384]

Convert 0.134L to cm3 and then calculate the radius.

[tanne]

Yep. That's it. Thank you!